Why b2 is paramagnetic

Test Series. Time it out for real assessment and get your results instantly. Test Yourself. Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test. Chemical Bonding and Molecular Structure.

Its structure according to VSEPR theory is octahedron trigonal bipyramid pentagonal bipyramid tetragonal bipyramid. The sp 3 d 2 hybridisation of central atom of a molecule would lead to: square planar geometry tetrahedral geometry trigonal bipyramidal geometry octahedral geometry. This is because of large size of F compared to H large size of N compared to F opposite polarity of N in the two molecules small size of H compared to N. ICl 2 - Species having the same number of bond pairs and lone pairs are isostructural have same structure.

There are two different explanations, which lead to the same conclusion, available. The more common one involves the formation of hybrid orbitals, which then form the molecular orbitals. I'm going to skip over this and focus on a hopefully clearer explanation. When combining atoms to molecules, the symmetry changes.

An isolated atom has the highest possible symmetry: spherical. The orbitals also transform according to this symmetry. This is clearly marked in the above scheme. Orbitals of similar energy and symmetry may again combine. The lighter the element, the closer these energy levels are together. The hybridisation scheme will arrive at the same conclusion.

The resulting diagram looks in approximation like this:. This results in a triplet ground state. The finished valence molecular orbital diagram is pictured below. Sign up to join this community. One of our academic counsellors will contact you within 1 working day. Please check your email for login details. Studying in Grade 6th to 12th? Registration done! Sit and relax as our customer representative will contact you within 1 business day Continue.

Why B2 is paramagnetic whereas C2 is diamagnetic? Enter email id Enter mobile number. CO has 4 bonding pairs and 1 antibonding pair so it has a bond order of 3. Problem : Predict the hybridization of the central atom in each of the following molecules.

HCCCH c. Tetrahedral--sp 3 b. Linear--sp c. Octahedral--d 2 sp 3 d. Trigonal Bipyramidal--dsp 3 e.